Question

log9(x+6)-log9x=log9 2

Answer 1

9 is base
I'm just asking whether this is even solvable

Answer 2

hint

\(\log_9(x+6)-\log_9(x)=\log_9(2)\\\log_9(\frac{x+6}{x})=\log_9(2)\\\frac{x+6}{x}=2\)

Answer 3

can you solve that?

Answer 4

that's what i ended up with

Answer 5

good work

Answer 6

well then what do you put as final answer
just that?

Answer 7

you can always check to see if your right here

http://www.wolframalpha.com/input/?i=log9%28x%2B6%29-log9%28x%29%3Dlog9%282%29

Answer 8

no

Answer 9

solve for x

Answer 10

\(\dfrac{x+6}{x}=2\)

Answer 11

multiply both sides by \(x\)

\(x+6=2x\)

Answer 12

u end up with 6=2?

Answer 13

oooh

Answer 14

no of course not, 6 is not equal to 2

Answer 15

ima dumbass

Answer 16

if you are having problems solving this, I would go back and review old material. You should not be working on logs if you cant solve this IMO

Answer 17

\(x+6=2x \implies x=6\)

Answer 18

lol thanks for the help