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OpenStudy (anonymous):
Perform the requested operation or operations. (5 points)
f(x) =(x-3)/8 ; g(x) = 8x + 3, find g(f(x)).
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OpenStudy (anonymous):
Does g(f(x))=x?
OpenStudy (anonymous):
probably
one says multiply by 8, then add 3
the other says subtract 3, then divide by 8
so one undoes the other
jimthompson5910 (jim_thompson5910):
\[\Large \color{red}{f(x) = \frac{x-3}{8}}\]
\[\Large g(x) = 8x+3\]
\[\Large g(x) = 8(x)+3\]
\[\Large g( \color{red}{f(x)}) = 8( \color{red}{f(x)})+3\]
\[\Large g( \color{red}{f(x)}) = 8\left( \color{red}{\frac{x-3}{8}}\right)+3\]
I'll let you simplify.
OpenStudy (anonymous):
So that is a yes?
jimthompson5910 (jim_thompson5910):
you tell me
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OpenStudy (anonymous):
8s cancel each other out, and the the 3s do as well
jimthompson5910 (jim_thompson5910):
yes, \(\LARGE 8\left(\frac{x-3}{8}\right) + 3\) simplifies to x
jimthompson5910 (jim_thompson5910):
You'll also find that f(g(x)) = x as well. That means f(x) and g(x) are inverses of one another.
OpenStudy (anonymous):
Thanks.
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