Question

PLEASE HELP!!
A circle has its center at (2,-4) and a radius of 6 units. what is the equation of the circle?

Answer 1

still confused

Answer 2

We can use the standard form a a circle with center (h,k)
\[(x-h)^2 + (y-k)^2 = r^2\]

Answer 3

We are given the center in form
Center = (h,k)
Center = (2,-4)
Radius (r)= 6

Answer 4

plug in the values in the equation i provided and that is the eq of the circle described

Answer 5

but what would x and y be

Answer 6

or would i find that out later?

Answer 7

x is your input
y is your output

Answer 8

plug in the integers given in to you so we could see exactly what kind of circle we are talking about

Answer 9

Would the answer be
(X+2)^2 + (y-4)^2=6 ?

Answer 10

@Deeezzzz

Answer 11

\[(x-h)^2 + (y-k)^2 = r^2 \] <- this is the equation of the circle
(h,k) <- center
r<- radius
since we have (2,-4) with a radius 6 that means that h = 2, k = -2, and r =6 . Just plug those values into the formula

Answer 12

So it would be (x-2)^2 + (y+4)^2=6^2.... Right?

@Usukidoll
@Deeezzzz

Answer 13

that's close. you just have to expand on the 6^2 part
6 x6 =?
otherwise the equation is correct.