Question

[Challenge!] Give me 2 "hard" factoring polynomial equation. If I can't solve it before 5 minutes, I will be your fan. :)

Answer 1

\[12x^2+10x-16 \]
\[9999x^2+9000x-4500 \]

no calculators.... no online materials... all by using the quadratic formula and the discriminant formula. Have fun :)

Answer 2

try
x^4 - 2x^3 - 20x^2 - 8x - 96

Answer 3

Hint :- factor 96

Answer 4

awww naw... we have to make it challenging and fun though ;)

Answer 5

(x+4) (x-6) (x+2) (x-2)

Answer 6

no cant be right because the numbers multiply out to +96

Answer 7

did you do that on your own??? xS
looks wolframish

Answer 8

this is not easy

Answer 9

Yup..I used Synthetic Division.....

Answer 10

(x + 4) is a factor

Answer 11

What is the right answer then?

Answer 12

(x^2 + 4)(x+4)(x-6)

Answer 13

OH fudge....I factored (x^2 + 4) thinking it was (x^2-4) /facepalm Thanks anyway.

Answer 14

he was close though

Answer 15

yes good effort

Answer 16

wanna try mine lol?

Answer 17

I dont think yours will factor

Answer 18

how can you tell? :P

Answer 19

I'm having a hard time in your problem xD Can you show me a step by step solution so that I could analyze it thoroughly?

Answer 20

I'm not going through that D:

Answer 21

you'll need to use quadratic formula i think

Answer 22

oh yeah... I gave the two formulas to use XDDDDDDDDDDDD

Answer 23

discriminant formula and quadratic formula. first formula is awesome.. because you already have the b^2-4ac part

Answer 24

then when you use quadratic formula, you find the roots ... and write in factor form, so in the end you did factor... just in extra steps :P

Answer 25

@UsukiDoll, regarding your first equation, this is my answer. \[(x-8) (x+\frac{ 17 }{ x-8})\]

Answer 26

oh my not even close...

Answer 27

What?! Can you please give me the answer? Just the final no need for solution. I will try to make a solution for that final answer.