i have a question
@UsukiDoll @phi @welshfella
hint: A^B * A^C = A^(B+C)
(add the exponents, keep the base)
The second one seems easier ... @Vocaloid explained it well :)
i did it think its a
another hint for the first question: A^B/A^C = A^(B-C)
i really dont know what that means at all
|dw:1436966626304:dw| simplify all your answer choices and see which one matches the question
remember that \( 9^2 \) means \( 9 \cdot 9\) and \(9^6 \) means \( 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9\) and when you multiply them you get \( 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9\) and you can use the "short way" by writing 9 with what as the little number in the upper right ? (to find the number, count the number of nines)
im not getting anything that's the answer
the first one give me=56 second=4 third=20 fourth=0
Do you know how to write \[ 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \] using 9 with a little number in the upper right ?
so those are the answers you get to choose from right
you know 56 4 20 0
to answer this question, you need to learn what the exponent (little number in the upper right) means examples: \[ 9^1 = 9 \\ 9^2 = 9 \cdot 9 \\ 9^3= 9 \cdot 9 \cdot 9 \] do you get that idea ? the little number tells you how many times 9 is multiplied by itself
right exactly
yes I did it
they start with \[ 9^2 \cdot 9^6 \] if we change to the "long way" to write that, it is \[ 9 \cdot 9 \ \cdot \ 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \]
now change the "long way" to the short way. Can you do that for \[ 9 \cdot 9 \cdot 9 \cdot 9\cdot 9\cdot 9\cdot 9\cdot 9 \] ?
yes
\[\huge x^n \times x^m \implies x^{n+m}\] \[\huge \frac{ x^n }{ x^m } = x^{n-m}\] I think that's more clear now.
not really am I right its a
For example \[\huge 5^6 \times 5^9 \implies 5^{6+9} = 5^{14}\]
oj thx
Np
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