Question

Factor: x^2-8x+17

Answer 1

Is my answer right, \[(x-8)(x+\frac{ 17 }{ x-8 })\]

Answer 2

there's a prime number ... so I highly doubt we can factor without the quadratic formula.
that's one strange root...since it's supposed to be all numbers

Answer 3

solve the equation u got and see it matches with the equation u got

Answer 4

are you aware of the discriminant formula \[b^2-4ac\]

Answer 5

I guess so...that's the formula for checking perfect trinomials right?

Answer 6

perfect square numbers

Answer 7

thts the formula to get the value of x ,,..u can say

Answer 8

Going back, is (x−8)(x+17/x−8) right?

Answer 9

a = 1
b = -8
c=17

Answer 10

@JustinSpeedster r u only askd to factorize it or get the values of x???

Answer 11

Factorize only.

Answer 12

probably to factor, but how? since 17 is a prime. The only combinations are
1 x 17
17 x 1

Answer 13

yeah its cool thennn.... by the way u got options???

Answer 14

I got no options.... sadly.

Answer 15

\[(-8)^2-4(1)(17) \] solve this first. do you have a perfect square ?

Answer 16

It's obviously not a perfect square.

Answer 17

But if we were to solve this: \[(x+8) (x+\frac{ 17 }{ x+8 }) = x^2 +8x+17\]

Answer 18

\[64-68 = -4 \] oh nice... we're going to have some imaginary i thing going on .

Answer 19

both of those aren't the right roots.

Answer 20

because roots are all numbers. You can't have variables in them

Answer 21

this equation has complex roots in them

Answer 22

x+8 distributed to x = x^2 + 8x

x+8 distrubted to x+17/x+8 leaves = 17

Answer 23

all wrong

Answer 24

How? What's wrong in that "sense"?

Answer 25

you have to use the quadratic formula... wow I keep on typing that you can't have variables in the roots

Answer 26

But I was asked not to use the quadratic formula.