Question

A family has 8 girls and 4 boys. A total of 2 children must be chosen to speak on the behalf of the family at a local benefit. What is the probability that 1 girl and 1 boy will be chosen?

Answer 1

dude i missed you!!! @DaBest21

Answer 2

there are 4/12 boys and 8/12 girls so lets say they pick girls first since they picked her she cant be picked again so now there is 11 to choose from instead of 12 so to find the probability do 4/11*8/12 and cross multiply the 4 (from 4/11) by the 8 (from 8/12) so 4*8 and do 11 (from 4/11) times 12(from 8/12) and put the answer to 4*8 on top of the fraction and the answer to 11*12 on the bottom

Answer 3

so what is 4*8 @thisotherliz

Answer 4

32

Answer 5

now what is 11*12

Answer 6

132

Answer 7

yes so make the fraction 32/132 which shows the probability of 1 boy and one girl being picked which can be simplified to 8/33

Answer 8

dont forget to medal and mention me if u need more help
p.s. it might be easier to send me a message if u need help so i can respond when helping others

Answer 9

the choices are 2/11 1/6 2/33 and 16/33

Answer 10

@DaBest21

Answer 11

one sec

Answer 12

okay

Answer 13

here 16/33

because there are 28 g/g pairs, 6 b/b pairs, and 32 g/b pairs. In total 66 pairs, and of those pairs 32/66 are 1 girl and 1 boy, reduced is 16/33.

Answer 14

let me double check @thisotherliz

Answer 15

oh okay thank you so much