Question

Brian has started a savings account. The balance, g(x), in his account can be represented by the function g(x) = 25x + 350, where x is the number of weeks he deposits money. Suppose 25 changed to 35. What does this mean in the context of the problem

Answer 1

25x is variable amount

Answer 2

answer choices
changing 25 to 35 means his initial deposit increased
changing 25 to 35 means his initial deposit decreased
changing 25 to 35 means the amount he deposits each week increased
changing 25 to 35 means the amount he deposits each week decreased

Answer 3

C

Answer 4

\(\large \begin{array}{llll}
g(x) = &{\color{brown}{ 25 }} x + &350\\
&{\color{brown}{ slope}}&y-intercept
\end{array}\qquad slope=\textit{rate of change}\)

Answer 5

he deposits in his acccount every "x" amount of weeks
originally it'd be every 25x weeks

if 25 changes to 35, then it'd be 35x
so he'd be depositing every 35x weeks

Answer 6

the hmm wording is a bit misleading
25x means... every "x" week he deposits 25 bucks

so say on week 1, x =1 and his deposit is 25(1)
week 2, x = 2 and his deposit is 25(2)
and so on

so if 25 changes to 35
then on week 1, he'd be depositing 35(1)
and on week 2, 35(2) and so on

Answer 7

Write the equation of a line with a slope of –1 and a y-intercept of –6

Answer 8

is it y =-x-6

Answer 9

\(\bf \begin{array}{llll}
f(x) = &{\color{brown}{ -1 }} x + &-6\\
&{\color{brown}{ slope}}&y-intercept
\end{array}\)

graph it away

Answer 10

yeap

Answer 11

Write the equation of the line that passes through (−3, 5) and (2, 10) in slope-intercept form

Answer 12

i think it is y=-5x-10

Answer 13

\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ -3}}\quad ,&{\color{blue}{ 5}})\quad
% (c,d)
&({\color{red}{ 2}}\quad ,&{\color{blue}{ 10}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ y_2}}-{\color{blue}{ y_1}}}{{\color{red}{ x_2}}-{\color{red}{ x_1}}}
\\ \quad \\
% point-slope intercept
y-{\color{blue}{ y_1}}={\color{green}{ m}}(x-{\color{red}{ x_1}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}
\)

Answer 14

same as the one before...
you may want to post anew, more eyes btw

Answer 15

slope is -5

Answer 16

y-int is -10

Answer 17

i did that and i got y=5x+8

Answer 18

hmmm got a typo darn it
\(\bf \begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
% (a,b)
&({\color{red}{ -3}}\quad ,&{\color{blue}{ 5}})\quad
% (c,d)
&({\color{red}{ 2}}\quad ,&{\color{blue}{ 10}})
\end{array}
\\\quad \\
% slope = m
slope = {\color{green}{ m}}= \cfrac{rise}{run} \implies
\cfrac{{\color{blue}{ 10}}-{\color{blue}{ 5}}}{{\color{red}{ 2}}-{\color{red}{ (-3)}}}\implies \cfrac{5}{2+3}\implies \cfrac{\cancel{5}}{\cancel{5}}\implies 1
\\ \quad \\
% point-slope intercept
y-{\color{blue}{ 5}}={\color{green}{ 1}}(x-{\color{red}{ (-3)}})\qquad \textit{plug in the values and solve for "y"}\\
\qquad \uparrow\\
\textit{point-slope form}\)