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Mathematics 9 Online
OpenStudy (anonymous):

The table below shows the data for a random sample of fish that were collected from and later released into a lake: How many catfish are estimated to be present if a sample of 800 fish is collected from the lake? 208 260 348 372

OpenStudy (anonymous):

OpenStudy (anonymous):

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OpenStudy (anonymous):

@dan815

OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

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OpenStudy (anonymous):

@DaBest21

OpenStudy (kropot72):

Add the numbers of Catfish, Grass carp and Bluegill that were in the sample. Call that total number n. Then the probability of a Catfish in a very large sample of fish is 52/n. Therefore to estimate the number of Catfish in a sample of 800 we need to calculate \[\large \frac{52}{n} \times \frac{800}{1}=you\ can\ calculate.\]

OpenStudy (anonymous):

@hotguy

OpenStudy (anonymous):

please helpppp xc

OpenStudy (anonymous):

@kropot72 i dont understand

OpenStudy (kropot72):

The total number of fish in the first sample is 52 + 61 + 87 = 200 Therefore to estimate the number of Catfish in a sample of 800 we need to calculate \[\large \frac{52}{200} \times \frac{800}{1}=?\]

OpenStudy (anonymous):

208 @kropot72

OpenStudy (kropot72):

Yes, 208 Catfish is correct.

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