Need help finding correct answer (work included):
A cyclist and her bicycle (combined mass of 75.0 kg) apply a force of 34.2 N. If the frictional force is -23.5 N, what will be the acceleration of the bicycle (in m/s2)?
@rajat97

Question

Need help finding correct answer (work included): 
A cyclist and her bicycle (combined mass of 75.0 kg) apply a force of 34.2 N. If the frictional force is -23.5 N, what will be the acceleration of the bicycle (in m/s2)?
@rajat97

summersnow8 · Answer

A cyclist and her bicycle (combined mass of 75.0 kg) apply a force of 34.2 N. If the frictional force is -23.5 N, what will be the acceleration of the bicycle (in m/s2)?

    not sure about this question 

    m: 75.0 kg     

F = 34.2 N    

Ff: -23.5 N     

a: ? 

    F = m * a
    
    34.2 N = 75.0 kg * a 

    a = 34.2 N 

Well, what is the net force on the bicycle, if cyclist plus bicycle exert force of 34.2 N and frictional force opposes to the tune of 23.5 N?  From that net force, work out acceleration

ΣF = 34.2 N - 23.5 N 

ΣF = 10.7 N 

F = m * a 

a = F / m 
a = 10.7 N / 75.0 kg 

a = 0.14266 m/s^2 

a = 0.143 m/s^2

nikato · Answer

yup. that looks correct. i got the same thing.

nikato · Answer

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