Question

An expression is shown below:

2x3y + 8xy − 4x2y − 16y

Part A: Rewrite the expression so that the GCF is factored completely. (4 points)

Part B: Rewrite the expression completely factored. Show the steps of your work. (6 points)

Answer 1

@pooja195

Answer 2

A)
2x3y + 8xy - 4x2y - 16y looks like we can take out a 2y

so 2y(x3 + 4x - 2x2 - 8)

Answer 3

B)
2y(x3 + 4x - 2x2 - 8) group like this
2y (x3 - 2x2) + (4x-8) then factor x^2 and 4
2Y x2(x-2) +4(x-2) factor out x-2
(2y)(x-2)(x2+4)

C) what do you think??

Answer 4

there is no c @Jacob902

Answer 5

anyways cool awesome hope you understand

Answer 6

2x^2y(x-2) +8y(x-2)
=> (x-2)(2x^2y+8y)
=>2y(x-2)(x^2+4)

Answer 7

is that for a or b? @princeharryyy

Answer 8

they are both.

Answer 9

so the same answer @princeharryyy

Answer 10

I assume "2x3y + 8xy - 4x2y - 16y" means 2x³y + 8xy - 4x²y - 16y. If not, ignore my answer.
Part A: 2y(x³ + 4x - 2x² - 8)

Part B: 2y(x(x² + 4) - 2(x² + 4)) = 2y(x - 2)(x² + 4)

Answer 11

See>>


for A))

for the first part as we don't know what the values of x and y are, they are both variables the highest common factor can be any of the three 2y or (x-2) or (x^2+4)

but as you know (x-2) is always less than (x^2+4) the GCF can only be 2y or (x^2+4) or (y or 2*(x^2+4))

Answer 12

So, the answer most probably cannot be determined, because the answer can be from any of those two.

Answer 13

for the second part >>>
2x^2y(x-2) +8y(x-2)
=> (x-2)(2x^2y+8y)
=>2y(x-2)(x^2+4)

was all >>> :) @mackenzieee

I hope u r getting, what I am trying to say.

Answer 14

okay I see now I am just a little confused on if that is showing my work for part b

Answer 15

write three steps that's all >> the stuff that you need.

Answer 16

okay thank you

Answer 17

thanks @Jacob902

Answer 18

u r welcome @mackenzieee