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Which of the following is equivalent to x2 < -2x? x x x x -2 0 -2 -1
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@iGreen
Well, you can divide 'x' to both sides. \(\sf x^2 < -2x\) \(\sf \dfrac{x^2}{x} < \dfrac{-2}{x}\)
It cancels on the right, giving us: \(\sf \dfrac{x^2}{x} < -2\) Now simplify the left side
please I still do not understand @iGreen
\(\sf x^2 \rightarrow x \cdot x\) So we have: \(\sf \dfrac{x \cdot x}{x} < -2\) Cancel out one of the \(\sf x\)'s on the top and one of the \(\sf x\)'s on the bottom.
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so is it x ?
Yes, it just leaves us with 'x'. So our final answer is: \(\sf x < -2\)
@iGreen thank you so much
Np
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