Question

Find the vertices and foci of the hyperbola with equation x squared over nine minus y squared over sixteen = 1

Answer 1

equatio of hyperbola is
\[\frac{ x^2 }{ 3^2 } - \frac{ y^2 }{ 4^2 } = 1\]

Answer 2

\[F_1 = (-c , 0) ~~~~and~~~~F_2 = (c , 0)\]

Answer 3

\[\frac{ x ^{2} }{ 9 }- \frac{ y ^{2} }{ 16 } =1\]

Answer 4

thats the equation

Answer 5

9 = 3^2
and 16 = 4^2

Answer 6

see standard equation of hyperbola is
\[\frac{ x^2 }{ a^2 } - \frac{ y^2 }{ b^2 } = 1\]

Answer 7

ohhh. sorry

Answer 8

not a big deal....... @egbeach
so now
\[c^2 = a^2 + b^2 \]

Answer 9

c^2= 25 so c=5

Answer 10

so now u can get focii??/

Answer 11

yeah! thank you

Answer 12

vertices???

Answer 13

(+3,0) and (-3,0) right?

Answer 14

yup :))))