Question

Please help :)
Describe the roots of the equation shown below.
64x^2-16x+1=0
A. There are two real, irrational roots.
B. There is one real, double root.
C. There are two real, rational roots.
D. There are two complex roots.

Answer 1

Do you have a y idea what it might be?

Answer 2

c

Answer 3

WHy?

Answer 4

have you solved?

Answer 5

You can use quadratic equation to solve

Answer 6

Yeah I know how to solve it but just not sure which one haha

Answer 7

Factor it.

Answer 8

both real and rational unless imaginary numbers were put into equation (Im assuming not so considering it wasnt mentioned in the question itself), and also one has negative coefficient, theres no need to even consider it. No need to solve

Answer 9

\[64x^2-16x+1=(8x-1)(8x-1)=0\]

Answer 10

\[8x-1=0 or 8x-1=0\]

Answer 11

so 1/8

Answer 12

\[x=\frac{1}{8}orx =\frac{1}{8}\]

Answer 13

1 Double Root

Answer 14

I'm so confused
so it's not two real rational like what Reealcheyenne said?

Answer 15

no

Answer 16

There is one root which occurs twice. That is what we call a double root. It corresponds to a point of tangency of the graph to the x axis at that number.

Answer 17

ohhh! alright thanks so much :)

Answer 18

yw