Question

Algebra Help?

Answer 1

\[\frac{ \sqrt{a}+2\sqrt{y} }{ \sqrt{a}-2\sqrt{y} }\]

Answer 2

Rationalize the denominator and simplify.

Answer 3

Why would it be the conjugate of the numerator and not the denominator? Shouldn't it be multiplied by \[\frac{ \sqrt{a}+2\sqrt{y} }{ \sqrt{a}+2\sqrt{y} }\]

Answer 4

u r correct

Answer 5

it should be
\[\frac{ \sqrt{a} + 2\sqrt{y} }{ \sqrt{a} - 2\sqrt{y}} \times \frac{ \sqrt{a} + 2\sqrt{y} }{ \sqrt{a} + 2\sqrt{y}}\]

Answer 6

Ok so that's the part I always have trouble with. I'm not the best at multiplying radicals.

Answer 7

\[(a - b) \times (a + b) = a^2 - b^2 \]

Answer 8

so it would be
\[\frac{ (\sqrt{a} + 2\sqrt{y})^2 }{ (\sqrt{a})^2 - (2\sqrt{y})^2 }\]