Question

Suppose ΔABC is an acute triangle. Let the bases of the altitudes at B and C be E and F, respectively. Prove ΔABC and ΔAEF are similar

Answer 1

I typed the question verbatim, but it sounds odd that E and F would be bases. I would think they would be points. Regardless of that, still am unsure of how to do the problem.

Answer 2

Oh, okay, so they really are supposed to be points E and F. Maybe I drew my picture wrong but, at least the way yours is drawn, you could maybe show FE is parallel to BC?

Answer 3

That is equivalent, but there is a simpler way here

Answer 4

Oh, thats equivalent to saying theyre similar? Saying those lines are parallel?

Answer 5

First establish trivially that \(\triangle OFB\sim\triangle OEC\) by \(AA\)