Which of the following vectors are orthogonal to (2,1)?
A. (1,2)
B. (-3,6)
C. (-2,-3)
D. (1,-2)
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OpenStudy (dominirican1013):
@ganeshie8
OpenStudy (dominirican1013):
@jamesr
OpenStudy (dominirican1013):
@dan815
OpenStudy (anonymous):
YOLO
OpenStudy (dominirican1013):
-.-
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OpenStudy (anonymous):
yess
OpenStudy (dominirican1013):
I need help
OpenStudy (anonymous):
ight whts up
OpenStudy (dominirican1013):
Is it B and D then
OpenStudy (chillout):
Do you remember the condition to be orthogonal?
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OpenStudy (chillout):
I.E. the dot product.
OpenStudy (anonymous):
aww ship i got to catch up
OpenStudy (dominirican1013):
Yes but is B and D
OpenStudy (anonymous):
i say its D
OpenStudy (dominirican1013):
It was right thanks though
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OpenStudy (anonymous):
what, D
OpenStudy (chillout):
\[\vec{a}^{\,}\cdot\vec{b}^{\,}=0 \rightarrow \sum_{1}^{i}a_{i}b_{i} = 0\] This is what you need to use.
OpenStudy (dan815):
hey orthogonal means these vectors are at 90 degree angle
OpenStudy (dan815):
othogonal or perpendicular
OpenStudy (dan815):
the slope for the vector given <2,1> Slope= 1/2 =
and a perpendicular slope to that would be 2/-1 =-2 which is the "negative reciprocal" of 1/2
we can see the slopes of each vectors given see which of those simplify to -2 slope
A)(1,2) slope = 2/1=2
B. (-3,6) Slope=6/-3=2/-1=-2 <--------
C. (-2,-3) Slope= -3/-2=3/2
D. (1,-2) Slope=-2/1 =-2 <------------
So you are right