Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following equations shows the path of the softball?

H(t) = −16t2 + 26
H(t) = −16t2 + 26t
H(t) = −16t2 + 8t + 18
H(t) = −16t2 + 18t + 8

Question

Omar throws a softball from a starting height of 8 feet, with an initial velocity of 18 feet per second. Which of the following equations shows the path of the softball?

 H(t) = −16t2 + 26
 H(t) = −16t2 + 26t
 H(t) = −16t2 + 8t + 18
 H(t) = −16t2 + 18t + 8

welshfella · Answer

note at time = 0  h = 8

anonymous · Answer

The starting height is the height at time zero. So you need to choose a function with H(0) = 8. And the velocity is the derivative of position, so you need the function with H'(0) = 18. What do you think?

anonymous · Answer

i think the answer is A

anonymous · Answer

If you put t=0 into A, do you get H(0) = 8 ?

welshfella · Answer

you get 26 if you put t = 0 into A

anonymous · Answer

just kidding its C

anonymous · Answer

Right on. Well done!

anonymous · Answer

thank you!

welshfella · Answer

put t = 0 into C and what do you get?

anonymous · Answer

You're welcome.

welshfella · Answer

?????

welshfella · Answer

Its D

welshfella · Answer

h is 8 when t = 0
h(0) = -16(0)^2 + 18(0) = 8 = 8

anonymous · Answer

plug O in for T and you get C

anonymous · Answer

were not trying to get 8 were trying to get 18

welshfella · Answer

plug 0 for t in C and you get h = 18
- but its not 18 at time 0  its 8

welshfella · Answer

believe me the answer is D

welshfella · Answer

Omar is not 18 feet tall!!   lol

anonymous · Answer

were trying to find the path of the softball

welshfella · Answer

I know  that
but if you want to accept the wrong answer its up to you