Question

Cant remember how to solve this...

Answer 1

Multiply.

5xy^5 / 3x^5y^3 * 6x^5y^6 / 25x^7y^10

Answer 2

-6x^5y^6 **

Answer 3

y^5 means y*y*y*y*y
if you divide that by y^3
\[ \frac{y\cdot y\cdot y\cdot y\cdot y}{y\cdot y\cdot y} = y\cdot y \cdot \frac{ y\cdot y\cdot y}{y\cdot y\cdot y}= y\cdot y= y^2\]
or the fast way: if you are dividing , subtract top exponent minus bottom exponent
i.e.
\[ \frac{y^5}{y^3}= y^2\]
notice 5-3=2

Answer 4

Okay thats ringing a bell...

Answer 5

but dont I need to simplify 25 and -6 into two smaller numbers?

Answer 6

is this the original problem:

\[ \frac{5xy^5}{3x^5y^3} \cdot \frac{-6x^5y^6 }{25x^7y^{10}} \]

Answer 7

Yes

Answer 8

if so, we multiply top times top and bottom times bottom
\[ \frac{5xy^5\cdot-6x^5y^6}{3x^5y^325x^7y^{10}} \]
and you can reorder the top (and bottom)
I would just start dividing the bottom into the top as much as possible

Answer 9

for example, I already figured out y^5/y^3 = y^2
so we can simplify to
\[ \frac{5xy^5\cdot-6x^5y^6}{3x^5y^325x^7y^{10}} \\
\frac{5xy^2\cdot-6x^5y^6}{3x^5\cdot 25x^7y^{10}} \]

Answer 10

3 in the bottom can divide into -6 up top, to get -2
I would move the minus sign "out front". we get
\[ -\frac{5xy^2\cdot2x^5y^6}{x^5 \cdot 25x^7y^{10}} \]

Answer 11

notice you have x^5 in the top and in the bottom. they "cancel out" (anything divided by itself is 1)
so you have
\[ -\frac{5xy^2\cdot2x^5y^6}{x^5 \cdot 25x^7y^{10}} = -\frac{5xy^2\cdot2y^6}{25x^7y^{10}}\]

Answer 12

notice you have 5 up top and 25 down below
25 is 5*5
so we have a 5/5 that cancel, and 5 remains down below.

Answer 13

Im trying to follow but im getting lost... I remember having to do the first step as ---

5*x*y^5/ 3*x^5*y^3 * 2*3*x^5*y^6/ 5*5*x^7*y^10

Answer 14

And then minus the exponents and all.

Answer 15

So I now have - 2/5

Answer 16

the way I do these (where everything up top is multiplied and everything down below is multiplied) is ignore everything except one thing up top and the same thing down below
for example, if we look just at 5 up top and 25 below
\[ \frac{5}{25} = \frac{5}{5\cdot 5} = \frac{1}{5} \]
and I would replace the 5 up top by 1 and the 25 below with 5
and *everything else stays the same*

Answer 17

***
5*x*y^5/ 3*x^5*y^3 * 2*3*x^5*y^6/ 5*5*x^7*y^10
***

yes that is good. (but is there supposed to be a minus sign in there) ?

Answer 18

Um okay?

Answer 19

Yes because of -6

Answer 20

ok. so if we just at the numbers we have
\[- \frac{5\cdot 2 \cdot 3}{3 \cdot 5 \cdot 5 }\]
one pair of 5's cancel, and so does the pair of 3's
so yes we get
\[ - \frac{2}{5} \]

Answer 21

now do the x's
\[ \frac{x\cdot x^5}{x^5\cdot x^7} \]
we could make the top x^6 and the bottom x^12
but I try to divide first. for example x^5 divided by x^5 cancels (i.e.=1)

Answer 22

is it clear how to simplify the x's or is it confusing?

Answer 23

So your talking about combining then but to try to divide first..

Answer 24

Do you mean subtract??

Answer 25

the rules might be confusing, but remember this:
for example
x^5 means x*x*x*x*x
and if we divide by x^7 = x*x*x*x*x*x*x
i.e.
\[ \frac{x\cdot x\cdot x\cdot x\cdot x}{ x\cdot x\cdot x\cdot x\cdot x\cdot x\cdot x}\]

Answer 26

I have this--

- 2y^2x^-2/ 5x^-4 y^-4

Answer 27

every time you have an "x" up top and "x" down below, they cancel out
so just cancel them out in pairs.

Answer 28

Final answer-

- 2/ 5x^6y^2

Answer 29

what do you get for
\[ \frac{x\cdot x^5}{x^5\cdot x^7} \]?

Answer 30

I would try to keep the exponents positive (less confusing)
\[ \frac{x\cdot \cancel{x^5}}{\cancel{x^5}\cdot x^7} = \frac{x}{ x^7}= \frac{1}{x^6}\]

Answer 31

Thank you for taking away 40 minutes of my time that I needed.

Answer 32

This question should of taken less then 5 minutes to solve.

Answer 33

Thank you for explaining things. But I did not need that. All I needed was a refresher. Im studying for my final exam.

Answer 34

oops
\[ -\frac{2}{5} \frac{1}{x^6y^2}\]

Answer 35

I figured that out 6 minutes ago..