The table below shows the number of marbles of different colors in a bag: Ursula draws a marble from the bag randomly without looking. She then draws another marble from the bag without replacing the first one. Which expression shows the probability of drawing black marbles in both the trials?
A
B AND C
@welshfella @Vocaloid @vera_ewing @omgitsjc @LegendarySadist
@Kash_TheSmartGuy
Where is the table?
here
i was thinking the answer would be a but idk
Are you sure that's the table? The question asks about black marbles, but the table you provided only talks about Red, blue, green, and purple.
crap wrong table
there but i was thinking (a) but im not sure
When you look for a probability of one thing it's simply \[\large \sf \frac{Desired~object}{Total~objcets}\] Which in this case is \[\large \sf \frac{black~marbles}{Total~marbles}\] When you look for it to happen twice, you multiply the probabilities. Since we're assuming the first will end up with a loss of one black ( and one total ) the second probability would look like this \[\large \sf \frac{black~marbles-1}{Total~marbles-1}\] Now you would just multiply the probabilities together so \[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
would it be a thats what i got
No, it's not a
c
or b idk
Why not just plug the numbers into what I gave you?
\[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
idkhowwwwwwwwwwwwwwwwwwwwwwwwwwwwww
How many black marbles are there?
10
How many total marbles are there?
16
@LegendarySadist
Now plug 10 in for black marbles and 16 for total marbles \[\large \sf \frac{black~marbles}{Total~marbles}~\times ~ \large \sf \frac{black~marbles-1}{Total~marbles-1}\]
d
You only showed A B and C as your options.
soooooooo what is it @LegendarySadist
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