Question

A system of equations is shown below:

-3x + 7y = -16
-9x + 5y = 16

Part A: Create an equivalent system of equations by replacing one equation with the sum of that equation and a multiple of the other. Show the steps to do this. (6 points)

Part B: Show that the equivalent system has the same solution as the original system of equations. (4 points)

Answer 1

@SithsAndGiggles

Answer 2

@wolf1728

Answer 3

@JoannaBlackwelder

Answer 4

@Elsa213

Answer 5

@eninone

Answer 6

@EllenJaz17

Answer 7

@princeharryyy

Answer 8

@peachpi

Answer 9

help please....

Answer 10

I can't do the steps as if now, that will take time and I've got a lot of work to do.
Sorry about that.

Answer 11

ok

Answer 12

anyone else im so lost

Answer 13

To create a new system of equation with the conditions given, let's take for example the first equation:
\[-3x+7y=-16\]
And let's forget about the "=" sign and center on the following expression:
\[-3x+7y+16\]
So I will add to it the second equation, multiplied by any number... let's say... 10...
\[(-3x+7y+16)+(10)(-9x+5y-16)\]
So, doing some simple algebra:
\[(-3x+7y+16)-90x+50y-160\]
Ending up with:
\[-93x+57y-144\]

And for the second part you'll have to solve the new system of equation formed by the new equation:
\[-93x+57y=144\]
\[-9x+5y=16\]

Answer 14

ty so much