At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liters, what must the temperature be for the gas pressure to remain constant?
A. 160 K
B. 273 K
C. 560 K
D. 140 K

Question

At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liters, what must the temperature be for the gas pressure to remain constant?
  A. 160 K 	
  B. 273 K 	
  C. 560 K 	
  D. 140 K

perl · Answer

Is there a formula given

perl · Answer

according to this https://www.chem.wisc.edu/deptfiles/genchem/sstutorial/Text9/Tx95/tx95.html

perl · Answer

Charles' Law states: If the pressure of a gas sample is kept constant, the volume of the sample will vary directly with the temperature in Kelvin (Figure 9.9).

perl · Answer

this means
T = k * V 
320 = k * 40
k = 320/40 = 8

T = 8*V 
Can you solve it now?

danica518 · Answer

pv=nRT

danica518 · Answer

P1*V1=n*R*320K
P2*V2=n*R*T2
P2=P1
and V2=20.0 or 1/2 of V1 so
P2*V2= P1*1/2V1=1/2(P1*V1)=1/2( n*R*320K)= n*R*160K
therefore 160K