Question

Challenge: Graph the equation with a diameter
that has endpoints at (-3, 4) and (5, -2). Label
the center and at least four points on the
circle. Write the equation of the circle.

Answer 1

hmm what's the distance between (-3, 4) and (5, -2). ?

Answer 2

eq.of circle is
(x-x1)(x-x2)+(y-y1)(y-y2)=0

Answer 3

About 9.90

Answer 4

So I divide that by two to get the radius right? And with it the center

Answer 5

@sewandowski hmmm how did you get 9.9?

Answer 6

Square root of: (-3-4)^2 + (5-(-2))^2

Answer 7

mid point is the center

Answer 8

Oooh, so I use the midpoint formula?

Answer 9

yes

Answer 10

hmm anyhow as @surjithayer said

find the diameter to get the "radius"
ahd the midpoint formula to get the center

Answer 11

btw, the distance aint' 9.9 either

Answer 12

Ok, so the midpoint of the points is (1,1), which is the center

Answer 13

yeap...1,1 is the center

Answer 14

and the diameter?

Answer 15

Ok, now I got 10

Answer 16

so the radius is 5

Answer 17

yeap

radius is 5, diameter is 10

then \(\large (x-{\color{brown}{ h}})^2+(y-{\color{blue}{ k}})^2={\color{purple}{ r}}^2

\qquad center\ ({\color{brown}{ h}},{\color{blue}{ k}})\qquad
radius={\color{purple}{ r}}\)

Answer 18

Perfect, now all I need to do is graph

Answer 19

Thanks guys!!

Answer 20

yw

Answer 21

eq. of circle is
\[\left\{ x-\left( -3 \right) \right\}\left( x-5 \right)+\left( y-4 \right)\left\{ y-\left( -2 \right) \right\}=0\]
solve it.