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Mathematics 7 Online
OpenStudy (anonymous):

Verify the identity. Justify each step. (PLEASE SHOW YOUR WORK)

OpenStudy (anonymous):

\[\frac{ \sec \theta }{ \csc \theta - \cot \theta } - \frac{ \sec \theta }{ \csc \theta +\cot \theta } = 2 \csc \theta \]

imqwerty (imqwerty):

1st talke lcm and write the equation

OpenStudy (anonymous):

I don't know how to do any of this

imqwerty (imqwerty):

What is the LCM of 1/2 and 1/3

OpenStudy (anonymous):

what does lcm mean?

imqwerty (imqwerty):

Least common multiple

OpenStudy (anonymous):

2 and 3?

OpenStudy (welshfella):

LCM is csc^2 O - cot^2O

OpenStudy (anonymous):

ok than what

imqwerty (imqwerty):

After taking the lcm we get the common denominator nd then we can do addition nd subtraction in the numerators.

OpenStudy (welshfella):

making it one fraction we get secO(csc^O + cot^2O) - secO(csc^2O - cot^2O) ----------------------------------------- csc^2 O - cot^2O = 2 secO cot^2O ----------- csc^2 O - cot^2O

OpenStudy (anonymous):

ok than what?

imqwerty (imqwerty):

After this ^ step convert all values in tems of sin and cos

OpenStudy (welshfella):

now csc^2 O = 1 + cot^2 O so the denominator = 1 so we are left with 2 sec O cot^2 O

OpenStudy (welshfella):

hmm might have slipped up somewhere cant get 2 csc O from that...

OpenStudy (welshfella):

yea i see where i went wrong when making it into one fraction its ecO(cscO + cot O) - secO(csc O - cot O) ---------------------------------- csc^2 O - cot^2O

OpenStudy (welshfella):

= 2sec O cot O = 2 *1 /cos O * ccos O / sin O = 2 csc O

OpenStudy (welshfella):

the denominator csc^2 O - cot^2O = 1 because csc^2 O = 1 + cot^2 O substituting;- 1 + cot^2 O - cot^2 O = 1

OpenStudy (lynfran):

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