Question

Jake says that the function is defined at x = –1, x = 3, and x = 4. Yoe says that the function is undefined at those x values. Who is incorrect? Justify your reasoning.

Answer 1

@Michele_Laino

Answer 2

f(x)=(x-1)(x+2)(x+4)/(x+1)(x-2)(x-4)

Answer 3

do you understand the function I wrote or should I draw i?

Answer 4

from the text of your problem I can write this expression for function f(x):
\[\Large f\left( x \right) = \frac{{\left( {x - 1} \right)\left( {x + 2} \right)\left( {x + 4} \right)}}{{\left( {x + 1} \right)\left( {x - 2} \right)\left( {x - 4} \right)}}\]

Answer 5

now we can not divide by zero, so we have to exclude those values of x, such that:
\[\Large \begin{gathered}
x + 1 = 0 \hfill \\
x - 2 = 0 \hfill \\
x - 4 = 0 \hfill \\
\end{gathered} \]
in other words we have to be certain that the denominator is not equal to zero

Answer 6

ok, i see

Answer 7

for example if I solve the first equation, I get:
x=-1
so I have to exclude that value

Answer 8

If I solve the second equation, I get:
x=2
again, I have to exclude the value x=2

Answer 9

similarly for third equation:
x-4=0
which gives:
x=4, and i have to exclude that value

Answer 10

ok:) I understand

Answer 11

ok!

Answer 12

So the answer would be? @Michele_Laino

Answer 13

Edward is right!

Answer 14

ok:) Thanks!!!

Answer 15

:)