Could someone check if I am on the right track? WILL FAN AND MEDAL!

Question

unofficialllyy · Answer

The holding tanks are congruent in size, and both are in the shape of a cylinder that has been cut in half vertically. The bottom of the tank is a curved surface. What is the volume of both tanks if the radius of tank #1 is 15 feet and the height of tank #2 is 120 feet? You must explain your answer using words, and you must show all work and calculations to receive credit.


So I know I have to use the formula for the volume of a cylinder which is $$V=\Pi r^2h$$

Since it's given that the radius is 15 and the height is 120, I plugged them into the formula. 

$$V=\Pi (15)^2(120)$$    Is this right so far?

unofficialllyy · Answer

@campbell_st

campbell_st · Answer

its makes sense to me... the congruent tanks form a cylinder, radius 15 and height 120

unofficialllyy · Answer

Then I do 15^2 which is 225. 
Then I multiply 225 and 120 to get 2700. 
Then I multiply pi and 2700 to get 2700pi, or in decimal form 8482.30016469

unofficialllyy · Answer

But it says it is cut in half vertically, so do I divide by 2?

unofficialllyy · Answer

@campbell_st

campbell_st · Answer

well I read the question as the tanks are congruent halves... 

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