Question

What is the equation of a circle that passes through (2, 0) and has its center at M(4, 0)?

Answer 1

please help!!!!

Answer 2

standard form of circle: (x - h)^2 + (y - k)^2 = r^2center is (h , k) and radius is rfor your circle, the center (h , k) is (1 , 2)so it will look like: (x - 1)^2 + (y - 2)^2 = r^2to find the radius squared, plug in the (x,y) point you know is on the circle -- (3 , 4)(3 - 1)^2 + (4 - 2)^2 = r^22^2 + 2^2 = 8 = r^2

Answer 3

???

Answer 4

Ok, so we know the standard form of a circle is (x - h) ² + (y - k) ² = r ² and the center is (h , k) and radius is r.
Does this make sense so far?

Answer 5

yes

Answer 6

!!!

Answer 7

How far is it from (4,0) to (2,0) ?

Answer 8

(2,0) ?? i dont know xD

Answer 9

do you see how they are 2 units apart ?