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Mathematics 20 Online
OpenStudy (anonymous):

Geometry Help PLEASE!!!

OpenStudy (owlcoffee):

What do you need help with?

OpenStudy (anonymous):

OpenStudy (anonymous):

@Owlcoffee

OpenStudy (owlcoffee):

So, what was stated, by mere definition implies that: \[\triangle SPT \sim \triangle RPQ \] This implies: \[\frac{ PS }{ PR }=\frac{ PT }{ PQ }=\frac{ ST }{ RQ }=k\] And that "k" is the proportionality coefficient. We do not need to know it, so we will relate the information we have: \[\frac{ PS }{ PR }=\frac{ PT }{ PQ }\] Those are the segment we will focus on in order to find what (60+x) is valued, and 60+x IS the segment PR: \[\frac{ 60 }{ 60+x }=\frac{ 48 }{ 48+36 }\] And solving for the whole expression "60+x" we just perform the proportion: \[60(48+36)=48(60+x)\] And isolate "60+x": \[60+x=\frac{ 60(48+36) }{ 48 }\]

OpenStudy (anonymous):

Thank you so much!

OpenStudy (logan13):

a.ss titty f.uck

OpenStudy (anonymous):

^^^ Dude seriously?

OpenStudy (logan13):

yes lol

OpenStudy (logan13):

ok sorry have a nice day im sorry i do this prank u see

OpenStudy (logan13):

sooo ya bye

OpenStudy (anonymous):

woooooooooooooooooooooooooooooooooooow @logan13

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