Mathematics
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OpenStudy (anonymous):
if sec(θ)= 5/3 and the terminal point determined by θ is in quadrant 4, then CHECK ALL THAT APPLIES
A. cos (θ)=3/5
B. csc (θ)= 5/4
C. tan (θ)= 4/3
D. sin (θ) = -(2/5)
10 years ago
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OpenStudy (danjs):
sec(theta) = 1 / cos(theta)
10 years ago
OpenStudy (anonymous):
what does that mean
10 years ago
OpenStudy (danjs):
sec(theta) = 1 / cos(theta) = 5 / 3
solve for cos(theta)
10 years ago
OpenStudy (danjs):
in quadrant 4, cos(theta) is positive
10 years ago
OpenStudy (danjs):
( x, y ) = ( cos(theta) , sin(theta) ) 4th quadrant, positive X value, positive cos value
10 years ago
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OpenStudy (anonymous):
so just A is right?
10 years ago
OpenStudy (danjs):
what is sin(theta 0if cos(theta) = 3/5 ?
10 years ago
OpenStudy (danjs):
sin^2(theta) + cos^2 (theta) = 1
10 years ago
OpenStudy (anonymous):
sin theta= 4/5
10 years ago
OpenStudy (anonymous):
Are A and B the corect answers?
10 years ago
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OpenStudy (danjs):
remember it is the 4th quadrant, the sin will be negative
10 years ago
OpenStudy (anonymous):
can you just tell me if im right
10 years ago
OpenStudy (danjs):
you know sin and cos, check the other 2 answers B and C
csc = 1 / sin = 5/4 ?
10 years ago
OpenStudy (danjs):
tan = sin / cos = 4 / 3 ?
10 years ago
OpenStudy (anonymous):
it cant be C because tangent has to be negative
10 years ago
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OpenStudy (danjs):
yes!
10 years ago
OpenStudy (anonymous):
I already knew that. I am asking if A and B are the correct answers
10 years ago
OpenStudy (danjs):
yes, we showed cos(theta) = 3 /5 so A is right.
You calculated sin(theta) = -4/5
10 years ago
OpenStudy (danjs):
so csc(theta) = 1 / sin(theta) = -5/4
10 years ago
OpenStudy (anonymous):
so are u saying B is right ?
10 years ago
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OpenStudy (danjs):
no, csc(theta) is negative
10 years ago
OpenStudy (danjs):
sin is -4/5
so 1 / sin is also negative
10 years ago
OpenStudy (anonymous):
so csc has to be -5/4 to be true
10 years ago
OpenStudy (danjs):
yeah
10 years ago
OpenStudy (anonymous):
thank you.
10 years ago
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OpenStudy (danjs):
so A is the only one it looks like
10 years ago
OpenStudy (danjs):
welcome
10 years ago