Question

ΔABC is translated 2 units down and 1 unit left. Then it is rotated 90° clockwise about the origin to create ΔA′B′C′. What are the coordinates of the vertices of ΔA′B′C′ ?
a) A′(-2, 0), B′(1, -1), C′(-1, -1)

b) A′(2, 1), B′(5, 0), C′(3, 0)

c) A′(-1, -2), B′(2, -3), C′(0, -3)

d) A′(-2, 1), B′(1, 0), C′(-1, 0)

http://cdn.ple.platoweb.com/PCAP-ASSETS-PROD/3978bcffcb214850a36be077c84be2b9

Answer 1

Lets start by A

Answer 2

A(0-1,0-2)
0-1 = -1
0 - 2 = -2
so when A is translated, its ordered pair becomes (-1,-2)

Answer 3

ok thanks i really don't know to much about geometry so

Answer 4

now we need to rotate that 90 clockwise
the rule for that is (y,-x)

Answer 5

ok

Answer 6

so if we put the ordered pair for A into (y,-x) we get
-2, 1

Answer 7

that is the ordered pair for A'

Answer 8

so the answer is a ?

Answer 9

If you want, we can find the ordered pairs for B and C but only 1 answer choice has (-2,1) for A

Answer 10

no not A
look for A'(-2,1)

Answer 11

ok yes we can do it

Answer 12

ok lets move on to B

Answer 13

ok

Answer 14

ordered pair (1,3)
2 units down
3-2 = 1
1 unit to the left
1-1 = 0
(0,1)
rotation 90 clockwise
(1,0)
so B'(1,0)

Answer 15

C
(1,1)
2 units down
1-2=-1
1 unit to the left
1-1=0
(0,-1)
rotation
(-1,0)

Answer 16

so A′(-2, 1), B′(1, 0), C′(-1, 0)

Answer 17

Did you get it?

Answer 18

yes

Answer 19

so the answer is ?