Step by step instruction?
\[\frac{ \sqrt{6} }{ \sqrt{5}-\sqrt{3} }\]
Rationalize the denominator and simplify.
the conjugate of the denominator is sqrt(5)+sqrt(3) (change the sign in the middle) \[\frac{ \sqrt{6} }{ \sqrt{5}-\sqrt{3}} * \frac{ \sqrt{5}+\sqrt{3} }{ \sqrt{5}+\sqrt{3}} \]
multiply all of that out and simplify. there should be no radicals left in the denominator when you're done
Ok well I think I'm left with \[\frac{ \sqrt{30}+\sqrt{18} }{ 2 }\] but I'm not sure if I did the math right.
actually, yeah, that's right
just know that you can simplify \[\sqrt{18} = 3\sqrt{2}\]
but other than that you've got the answer
Ok I'm not really sure how to simplify \[\sqrt{18}\] to get \[3\sqrt{2}\] is there a process to get there?
\[\sqrt{18}=\sqrt{9*2}=\sqrt{3*3*2}=3\sqrt{2}\]
So how would I do that to the \[\sqrt{30}\] or can't I? would it look like this: \[\sqrt{5*3*2}\]
you can't, the square root of 30 is already simplified
we can simplify the square root of 18 because it contains a perfect square (9) as a factor you can write square root of 30, no need to do anything else to it
so your final answer would be \[\frac{ \sqrt{30}-3\sqrt{2} }{ 2 }\]
Ok yeah I think I get it thank you.
*small correction, there should be a plus sign in the numerator
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