An expression is shown below: f(x) = –16x2 + 22x + 3 Part A: What are the x-intercepts of the graph of the f(x)? Show your work. (2 points) Part B: Is the vertex of the graph of f(x) going to be a maximum or minimum? What are the coordinates of the vertex? Justify your answers and show your work. (3 points) Part C: What are the steps you would use to graph f(x)? Justify that you can use the answers obtained in Part A and Part B to draw the graph. (5 points)
@Australopithecus
campbell_st
@campbell_st
@Keigh2015
can you help??
I am sorry this type of math is not my strong suit.
@misssunshinexxoxo can you help this person with their math?
its okay
Hi
This might help http://www.wolframalpha.com/input/?i=f%28x%29+%3D+%E2%80%9316x2+%2B+22x+%2B+3
well you need to factor the equation start with factoring out the negative... \[f(x) = -(16x^2 - 22x - 3)\] next multiply 16 and - 3 so -48 find the factors of -48 that add to -22 the larger factor is negative its a relatively easy pair to find...
i got −(8x+1)(2x−3)
that's correct so so to find the x-intercepts you need to solve 8x + 1 = 0 and 2x - 3 = 0 what values do you get...?
one minute
-1\8 and 3\2
thats what i got
ok so that's good now part B is it a maximum or minimum...?
you need to look at the sign of the leading coefficient
i have no clue @campbell_st
do you know what the coefficient is?
what is the leading term in the equation..?
-16 ?
so if its positive then you have a minimum, if its negative you have a maximum
oooh
great so which do you have, max or min...?
its both ??
-1\8 is max and and 3\2 in min >??
no if the leading coefficient is negative... do you have a max or min,,, it can't be both
here is the equation \[f(x) = -16x^2 + 22x + 3\] you said the leading coefficient is -16 that's correct... so if its a potive value you have a minimum if its negative you have a maximum so which do you choose
max
great... now the vertex
the easiest way is to find the line of symmetry do you know about that...?
no
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