Question

A box of 15 parts contains 7 that are defective. A worker picks parts one at a time and attempts to install them. Find the probability of each outcome in​ (a) through​ (d).
​(a) The first two chosen are both good.
nothing ​(Round to four decimal places as​ needed.)

Answer 1

Please check your question, which probably contains typo(s) and incomplete.
Cannot have 15 parts of which 77 are defective.

Answer 2

it a 7

Answer 3

P(two are good)
\[=\frac{C _{2}^{8} }{C_{2}^{15} }\]=?

Answer 4

30

Answer 5

ok im so lost 8/15

Answer 6

and 054

Answer 7

pl help me out

Answer 8

im so lost and dum

Answer 9

(a)
Initially, there are 8 good out of 15, so probability of getting the first good one is 8/15.
For the next one, there are only 7 good out of 14, so probability is 7/14.
For this two step experiment, the probability of getting 2 good out of two is therefore (8/15)*(7/14)=4/15.
Alternatively, you could use the formula by @Surjithayer