Rewrite in simplest radical form 1 x −3 6 . Show each step of your process.
\[\frac{\frac{1}{x}}{6^{-3}}=\frac{216}{x}\]
\[\mathrm{Apply\:exponent\:rule}:\quad \:a^{-b}=\frac{1}{a^b}\] \[6^{-3}=\frac{1}{6^3}\] \[=\frac{\frac{1}{x}}{\frac{1}{6^3}}\] \[\mathrm{Divide\:fractions}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}\] \[=\frac{6^3}{x}\]
are you understand @boots_2000
nope
not at all
1 over x raised 3 over 6 thats what the question was supposed to be
\[\huge\rm \frac{ 1 }{ x^\frac{ 3 }{ 6 } }\] like this ?
yes
alright you can reduce the fraction 3/6 =?
1/2
yep right now you can change 1/2 root to radical \[\huge\rm x^\frac{ m }{ n } = \sqrt[n]{x^m}\]
so my answer would be square root x of 1?
nope
\[\huge\rm x^\frac{ 1 }{ 2}=???\] let m = 1 and n =2 look at the exapmle i gave you
example*
yesright
sorry i didn't see word square so now you are not allowed to have radical at the denominator
\[\frac{1}{x^{\frac{3}{6}}}=\frac{1}{\sqrt{x}}\] \[\mathrm{Simplify}\:\frac{3}{6}:\quad \frac{1}{2}\] =1/x^(1/2) \[=\frac{1}{\sqrt{x}}\]
\[\sqrt[2]{x ^{1}}\]
\[\huge\rm \frac{ 1 }{ \sqrt{x}}\] multiply both the denominator and numerator by square root of x
don't forget the 1 at the numerator that stay there
\[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\]
\[1\div \sqrt[2]{x ^{1}}\]
like that?
yes right now multiply both the top and bottom by the denominator (sqrt{{x}) = answer
\[-\sqrt[2]{x ^{1}}\]
nope how did you get negative sign or is it typo ? ;)
typo
btw radical sign mean square root so you don't have to write 2 .....
sorry
\[\sqrt{ }\] <-- square root
\[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\] multiply denominator by denominator and numerator y numerator
so the answer is without the negative sign???
so its just the suare root of x that we just put but withour the negative???
well there isn't any negative sign in the original question so it's pretty obvious :=) o^_^o
nope multiply
\[\huge\rm \frac{ 1 }{ \sqrt{x} } \times \frac{ \sqrt{x} }{ \sqrt{x} }\] \[\frac{ 1 \times \sqrt{x} }{ \sqrt{x} \times \sqrt{x}}\]
okay well im lost so imma just guess or not answer it
as you wish.. just one last step MULTIPLCATION! that's it done!
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