Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Find the solution(s) to the following system of equations: y = 5 y = 3x - 4 Write answer as an ordered pair(s). Separate by a comma if more than one solution. what is the x ordered pair

OpenStudy (danjs):

If y = A and y = B, then set A = B, solve for the X value

OpenStudy (danjs):

5 = 3x - 4

OpenStudy (anonymous):

I got -1 ?

OpenStudy (danjs):

5 + 4 = 3x - 4 + 4 9 = 3x x = 3 y = 5 is already given

OpenStudy (anonymous):

the answer that I have is 3,5 but it's wrong

OpenStudy (danjs):

the point (3,5) is where the two lines intersect

OpenStudy (anonymous):

I got 239?

OpenStudy (usukidoll):

how is (3,5) wrong though? It does satisfy both equations

OpenStudy (anonymous):

the y axis is right but the x axis isn't

OpenStudy (danjs):

are you trying to put this in a computer test

OpenStudy (usukidoll):

could be mymathlab stuff ?! that was horrible when I took Calculus II

OpenStudy (danjs):

you said you put 3,5 try (3,5)

OpenStudy (anonymous):

I have in like that (3,5)

OpenStudy (usukidoll):

some sites are so super sensitive even though you have the right answer.

OpenStudy (usukidoll):

what site are you using @Aliypop ?

OpenStudy (anonymous):

It's called Moodel

OpenStudy (anonymous):

The y-coordinate is correct. Check the x again by graphing the system. thats the reply my teacher left

OpenStudy (usukidoll):

omg..... that means we have to use the graphing method

OpenStudy (usukidoll):

I would put a side note.... yo man solving for x helps too ...there's more than one method to solve a problem as long as it doesn't break math rules geez.

OpenStudy (usukidoll):

so I guess we have to graph y = 5 and y = 3x-4 -_-

OpenStudy (anonymous):

okay

OpenStudy (usukidoll):

so y = 5 means that our x is set at 0 so draw a horizontal line at (0,5)

OpenStudy (anonymous):

okay

OpenStudy (usukidoll):

and then for y = 3x-4 we have to let x be any number like x = 0,1,2,3 solve for y and plot points

OpenStudy (anonymous):

ok

OpenStudy (usukidoll):

that's about it.. if x = 3 there should be intersection... honestly... more than one method works... wow.

OpenStudy (usukidoll):

I'm just peeved at what your teacher wrote like... dude come on

OpenStudy (anonymous):

my teacher isn't the best I'm serious

OpenStudy (usukidoll):

yeah it already shows smh

OpenStudy (anonymous):

this is just a summer school class and I'm almost done I'm ahead of the class and she go upset about it

OpenStudy (usukidoll):

LOL! XD

OpenStudy (usukidoll):

what was her reason to be upset at you though?

OpenStudy (anonymous):

because 1 I was far ahead of the class , I came from a online home school so I'm usually ahead of my classes anyways

OpenStudy (usukidoll):

that's good.

OpenStudy (usukidoll):

getting ahead is the best thing ever...even I got blasted for being ahead in my computer classes but I just didn't care about what my professors said.

OpenStudy (anonymous):

but i'm going to public high school they want me to finish on pace with the rest, also is the answer 0,5

OpenStudy (usukidoll):

hmmm... if we're going to use the graphing method we have to graph y = 5 which is a horizontal line. Since x isn't given, it's already 0. so we have a horizontal line at (0,5) then for y=3x-4 we let x = 0,1,2,3... and solve for y to get points. we then use that information to graph until we find the point of intersection with is (3,5)

OpenStudy (usukidoll):

it is supposed to be (3,5) that's the point of intersection.... but since it's the graphing method instead of substitution method then we graph 2 lines.

OpenStudy (usukidoll):

did you graph y = 5 and y = 3x-4 ?

OpenStudy (anonymous):

I had gotten -2

OpenStudy (usukidoll):

oh were you solving for y =3x-4 by letting x = 0,1,2,3 ?

OpenStudy (anonymous):

I got -3 with zero

OpenStudy (usukidoll):

wait... for y = 3x-4 (just focus on that equation...nevermind the y =5) if x = 0 then y = -4...so we have one point (0,-4)

OpenStudy (usukidoll):

|dw:1437396892108:dw|

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!