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OpenStudy (guccidothedishes):
** will medal and fan
What are the explicit equation and domain for an arithmetic sequence with a first term of 5 and a second term of 2?
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OpenStudy (guccidothedishes):
n=5−2(n−1);allintegerswheren\[≥1
an=5−2(n−1);allintegerswheren\[≥0
an=5−3(n−1);allintegerswheren\[≥1
an=5−3(n−1);allintegerswheren\[≥0
OpenStudy (guccidothedishes):
@liljj1421 ??
OpenStudy (guccidothedishes):
@Michele_Laino
OpenStudy (michele_laino):
hint:
we can write this:
\[\Large \begin{gathered}
{a_2} = {a_1} + d \hfill \\
2 = 5 + d \hfill \\
\end{gathered} \]
where d is the sequence constant
OpenStudy (michele_laino):
what si d?
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OpenStudy (michele_laino):
after that the general formula, for the n-th term is:
\[\Large {a_n} = {a_1} + \left( {n - 1} \right)d\]
where a_1=5
OpenStudy (guccidothedishes):
how do I get d ?
OpenStudy (michele_laino):
it is simple, from the second equation, I can write:
\[d = 2 - 5 = ...?\]
OpenStudy (guccidothedishes):
so D=3 ?
OpenStudy (michele_laino):
no, d=-3
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OpenStudy (guccidothedishes):
okay so I can already eliminate 2 of the answer choices
OpenStudy (guccidothedishes):
but how do I determine the second part of the answer?
OpenStudy (michele_laino):
yes!
furthermore, please keep in mind that we start to count from n=1
OpenStudy (guccidothedishes):
So my answer is C
OpenStudy (michele_laino):
yes! That's right!
since if n=1, we get:
\[{a_1} = {a_1} + \left( {1 - 1} \right)d = 5 + 0 \times \left( { - 3} \right) = 5\]
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OpenStudy (guccidothedishes):
Thank you so much :)
OpenStudy (michele_laino):
:)
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