Question

Peter is giving marbles to some children at a carnival. He has 5 red marbles, 4 blue marbles, and 3 yellow marbles. If Peter selects a marble randomly without looking, what is the probability that he will give a blue marble to the first child and then a yellow marble to the second child?

4 over 12 plus 3 over 12 is equal to 7 over 12
4 over 12 plus 3 over 11 is equal to 80 over 132
4 over 12 multiplied by 3 over 12 is equal to 12 over 144
4 over 12 multiplied by 3 over 11 is equal to 12 over 132

Answer 1

@misssunshinexxoxo

Answer 2

@cupcakerain

Answer 3

@Tabby_012 @night.soul45

Answer 4

i will fan and medal

Answer 5

Which do you believe it is?

Answer 6

c or b @misssunshinexxoxo

Answer 7

@misssunshinexxoxo

Answer 8

@LynFran

Answer 9

The initial number of marbles is 12, of which 4 are blue. Therefore the probability of selecting a blue marble first is 4/12. Having selected a blue marble, there is a total of 11 marbles remaining of which 3 are yellow. Therefore the probability of a yellow marble being selected second is 3/11.
The required probability is therefore given by
\[\large \frac{4}{12}\times\frac{3}{11}\]

Answer 10

0.0909090909 @kropot72

Answer 11

i got it thanks

Answer 12

np.