Help with arithmetic/geometric sequences and series problem please
The problem is in the attached file
what does is mean by describe the four quantities? Don't the quantitates mean the same thing in all four formulas?
the quantities are the the variables like a_1,n,d,a_n in the problem a and a_1,n,r,a_n in problem c
do you know what a_1 means?
the subscript there basically tells you
for example a_6 is the 6th term in the sequence
which choice a or c represents an arithmetic sequence ? and of those choices one if a geometric sequence. an example of an arithmetic sequence is 3,7,11,15,... notice each term minus it's previous is the same number this number is the common difference an example of a geometric sequence is 2,4,8,16,... notice each term divided by its previous is the same number this number is the common ratio what do you think the d represents ? what do you think the r represents?
d represents the difference and r represents the common ratio @freckles
great d represents the common difference of an arithmetic sequence and r represents the common ratio of a geometric sequence
I'm confused though because in the problem it says to describe the four quantities for each formula, but would the quantities be the same in each formula
for example wouldn't a_1 mean the first term in the sequence no matter what formula it is?
@freckles
yes a_1 can mean the first term in the sequence
ok, so how do I answer the second part of the question? @freckles
I don't know which 3 to use for example in a do they want us to use a_1, n, and d to find a_n or do they want us to use a_1,a_n,n to find d or do they want us to use a_n,n,d to find a_1 or do they want us to use a_1,a_n,d to find n or do they want us to do each possibility of what they could mean
I'm not sure about that either, I'm assuming they want us todo each possibility. Could you just show me how to do it for 1 of the formulas and I can figure it out for the other ones? @freckles
\[a_n=a_1+d(n-1) \\ \text{ if we have } a_1,d, \text{ and } n \text{ just follow the order of operations \to find } a_n \\ \\ a_n=a_1+d(n-1) \\ \\ \text{ if we have } a_n,a_1,n \text{ then we can find } d \text{ by doing } \\ a_n-a_1=d(n-1) \text{ subtract } a_1 \text{ on both sides } \\ \frac{a_n-a_1}{n-1}=d \text{ divided both sides by} (n-1) \\ \] then you can do something similar for the other two possibilties just solve the equation for n also solve the equation for a_1
ok so it's pretty simple
thanks!
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