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If I knew all the other values except for n, how would I solve for n in this equation: a_n=a_1 r^((n-1) )
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Here is the equation in a better format
best way would be to take natural logarithm on both sides
and use lograthim properties.
is there a simpler way to do it? Because I haven't learned how to do that yet
specifically you can use log(ab) = loga + logb property here
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okat let me think
ok thanks
Usually, when you are solving for an exponent, you need to use logarithms.
\[a _{n}/ a _{1} = r ^{n-1}\]
Solve LHS. and transform it to a form which is similar to RHS. Then compare
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Yes I think mathstudent55 is true. But there's one exception, if a_n/a_1 can be written as r^x, then x=n-1. That's the case I can think of solving this without using logarithm.
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