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Mathematics 14 Online
OpenStudy (anonymous):

If I knew all the other values except for n, how would I solve for n in this equation: a_n=a_1 r^((n-1) )

OpenStudy (anonymous):

Here is the equation in a better format

OpenStudy (anonymous):

best way would be to take natural logarithm on both sides

OpenStudy (anonymous):

and use lograthim properties.

OpenStudy (anonymous):

is there a simpler way to do it? Because I haven't learned how to do that yet

OpenStudy (anonymous):

specifically you can use log(ab) = loga + logb property here

OpenStudy (anonymous):

okat let me think

OpenStudy (anonymous):

ok thanks

OpenStudy (mathstudent55):

Usually, when you are solving for an exponent, you need to use logarithms.

OpenStudy (a_clan):

\[a _{n}/ a _{1} = r ^{n-1}\]

OpenStudy (a_clan):

Solve LHS. and transform it to a form which is similar to RHS. Then compare

OpenStudy (anonymous):

Yes I think mathstudent55 is true. But there's one exception, if a_n/a_1 can be written as r^x, then x=n-1. That's the case I can think of solving this without using logarithm.

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