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OpenStudy (anonymous):
Challenge! Ready? What are the values of x and y?
http://assets.openstudy.com/updates/attachments/55ade084e4b071e6530cdc81-lollygirl217-1437459025179-as.jpg
Hint...they both end in a fraction
10 years ago
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OpenStudy (anonymous):
Hint...they both end in a fraction
10 years ago
OpenStudy (anonymous):
So do you need help or what?
10 years ago
OpenStudy (anonymous):
We know that: \(\angle BAD \cong \angle CBD\)
10 years ago
OpenStudy (anonymous):
no.....it is a challenge
10 years ago
OpenStudy (anonymous):
Suppose the angle is \(\theta\).
Then: \[
\sin(\theta) = \frac{y}{15+x} = \frac{8}{17} = \frac{x}{y}
\]Also: \[
\cos(\theta) = \frac{17}{15+x} = \frac{15}{17} = \frac{8}{y}
\]
10 years ago
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OpenStudy (anonymous):
x= what y=what; that is how the answer is placed
10 years ago
OpenStudy (anonymous):
I'm not going to do someone else's homework
10 years ago
OpenStudy (anonymous):
Look on my profile...this is what I do.
10 years ago
OpenStudy (anonymous):
I just had a professor answer one of my challenges.
10 years ago
OpenStudy (anonymous):
anyone??
10 years ago
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OpenStudy (welshfella):
you can apply the pythagoras theorem to large and smallest triangles
(15 + x)^2 = 17^2 + y^2
y^2 + x/62 + 8^2
10 years ago
OpenStudy (welshfella):
* y^2 = x^2 + 8^2
10 years ago
OpenStudy (welshfella):
substituting y*2 = x^2 + 8^2 into the first equation
(15 + x)^2 = 17^2 + x^2 + 8^2
10 years ago
OpenStudy (anonymous):
They both end in a fraction
10 years ago
OpenStudy (anonymous):
This is easy
10 years ago
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OpenStudy (welshfella):
yea
10 years ago
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