Question

***PLEASE HELP! WILL MEDAL***
Express answer in exact form.

Given a circle with an 8" radius, find the area of the smaller segment whose chord is 8" long

and is there any way to put the answer in this format?:
https://suwannee.owschools.com/media/g_geo_2013/8/q254_x.gif

Answer 1

@dan815

Answer 2

@jamesr

Answer 3

Since all sides are 8", they form an equilateral triangle.
The area of the sector is pi*r^2*60/360
Subtract the area of the triangle, that leaves the sector.
---------------
Sector = pi*64*/6 = 32pi/3 sq inches
Area of triangle = 4*8*cos(30) = 16sqrt(3)
Area of segment = (32pi/3) - 16sqrt(3)

Answer 4

Thanks

Answer 5

U WELCOME my b caps