Question

*(FAN AND MEDAL) HELP!!!

Answer 1

@pinkbubbles @ganeshie8

Answer 2

I NEED THE LAST 3 PLEASE I REALLY NEED HELP GUYS

Answer 3

i appreciate please help me!!!

Answer 4

@Vocaloid

Answer 5

@Haseeb96 ??? please :(

Answer 6

@campbell_st

Answer 7

@dan815

Answer 8

@Michele_Laino

Answer 9

@undeadknight26 @mathmath333

Answer 10

help :(

Answer 11

All of them need answered?

Answer 12

question 4)
hwre we have to evaluate this quantities:
\[\Large f\left( {10} \right) = ...?\;f\left( 3 \right) = ...?\]

Answer 13

oops..these*

Answer 14

(10)(3)

Answer 15

?

Answer 16

30?

Answer 17

you have to use your function:
\[\Large f\left( x \right) = 2 \times {3^x}\]

Answer 18

ok, wait

Answer 19

idk ;/

Answer 20

you have to replace x with 3 and x with 10

Answer 21

oh

Answer 22

f (3) = 2 x 3^10

Answer 23

@Michele_Laino

Answer 24

are you there @Michele_Laino ?

Answer 25

@Michele_Laino

Answer 26

hint:
\[\Large \begin{gathered}
f\left( 3 \right) = 2 \times {3^3} = 2 \times 27 = ...? \hfill \\
f\left( {10} \right) = 2 \times {3^{10}} = ...? \hfill \\
\end{gathered} \]

Answer 27

wait

Answer 28

f(10) is a very big number, so please use a calculator

Answer 29

i use wolfram i copy and paste: 0?

Answer 30

yes!

Answer 31

so whats nexts?

Answer 32

now we have to compute the same quantities, using this function:
\[\Large g\left( x \right) = 3 \times {4^x}\]

Answer 33

where its the formula, or its the same formula?

Answer 34

namely we have to evaluate these quantities:
\[\Large \begin{gathered}
g\left( 2 \right) = 3 \times {4^2} = 3 \times 16 = ...? \hfill \\
g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\
\end{gathered} \]

Answer 35

g(2) = 3x4^2 = 3x16 = 48?
g(10) = 3x4^10 = 0?

Answer 36

im right?

Answer 37

48 is right!
the second is a very big number
g(10)=3*1048576=...?

Answer 38

since 4^10=1,048,576

Answer 39

what i need to do now?

Answer 40

next ste:
we have to write the function of Carter

Answer 41

how?

Answer 42

we have to read the text of your problem

Answer 43

I think that the function used by Carter is:
\[\Large h\left( x \right) = 10 \times {2^x}\]
am I right?

Answer 44

yes i think so

Answer 45

ok! now we have to compute these quantities:
\[\Large \begin{gathered}
h\left( 2 \right) = 10 \times {2^2} = 10 \times 4 = ... \hfill \\
h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\
\end{gathered} \]

Answer 46

carter: 10(2)^x?

Answer 47

ok

Answer 48

sorry I have made an error, we have to compute g(3) and h(3) not g(2) and h(2)

Answer 49

\[\Large \begin{gathered}
g\left( 3 \right) = 3 \times {4^3} = 3 \times 64 = ...? \hfill \\
g\left( {10} \right) = 3 \times {4^{10}} = ...? \hfill \\
\end{gathered} \]

\[\Large \begin{gathered}
h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = ... \hfill \\
h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = ... \hfill \\
\end{gathered} \]

Answer 50

h(2)=10x2^2=10x4= 40?
h(10)=10x2^10x1024= 10485760?

Answer 51

im not sure about the last one, but im right?

Answer 52

we have:
\[\Large \begin{gathered}
h\left( 3 \right) = 10 \times {2^3} = 10 \times 8 = 80 \hfill \\
h\left( {10} \right) = 10 \times {2^{10}} = 10 \times 1024 = 10240 \hfill \\
\end{gathered} \]

Answer 53

so...

Answer 54

so, we have completed the question 4)

Answer 55

yea, but whats nexts? i did something wrong?

Answer 56

I think you have done right!

Answer 57

now we have to compare the graph of the new function of Amber, with the graph of the old function of the same Amber

Answer 58

the new function is:

\[\Large {g_2}\left( x \right) = 3 \times {4^x} + 45\]

whereas the old function is:

\[\Large {g_1}\left( x \right) = 3 \times {4^x}\]

Answer 59

i need to solve that? right?

Answer 60

I think that we have to draw both those graphs

Answer 61

im not good doing graph ;(

Answer 62

it is simple, the graph of the old function is like below: