If 2.0 liters of oxygen gas react with excess carbon monoxide at 273 K and 1.00 atm, how many liters of carbon dioxide can be produced under the same conditions?
2 CO (g) + O2 (g) yields 2 CO2 (g)
1.0 L
2.0 L
4.0 L
6.0 L
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OpenStudy (anonymous):
@jfraser
OpenStudy (anonymous):
would it be d?
OpenStudy (jfraser):
Nope. Look at the molar ratios from the reaction
OpenStudy (jfraser):
One mole of \(O_2\) will produce two moles of \(CO_2\)
OpenStudy (anonymous):
ik iget so b? @jfraser
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OpenStudy (jfraser):
Nope. 2L of \(O_2\) will produce \(twice\) that volume of \(CO_2\)
OpenStudy (jfraser):
Always remember that balanced equations give \(ratios\), not absolute amounts to work with
OpenStudy (anonymous):
oh so a thanks @jfraser
OpenStudy (jfraser):
It's not a, you did the ratio backwards
OpenStudy (rushwr):
@JFraser is it 4L?
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OpenStudy (photon336):
the key here is that you know carbon monoxide is in excess, so essentially o2 is your limiting reagent and you have to use that to figure out how many moles of CO2 are produced. once you do that you can figure out the answer.