Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (nuccioreggie):

;elp

OpenStudy (nuccioreggie):

@Michele_Laino. Please explain

OpenStudy (nuccioreggie):

@DanJS. P)ease explain. Both parts please

OpenStudy (danjs):

To find the probability of hitting the black circle, you have to compare the area of the circle to the area of the white region

OpenStudy (danjs):

They give you the diameter is 2, so the radius is 1, and the area of a circle is pi*r^2 = pi* 1 = pi

OpenStudy (danjs):

The area of the white region , is the area of the square take away the area of the circle 100 - pi

OpenStudy (nuccioreggie):

Ok can u explain both answers please

OpenStudy (danjs):

you get that part

OpenStudy (danjs):

The probability of hitting the black circle is the ratio of the two areas... \[\frac{ Area~circle }{ Area~white } = \frac{ \pi }{ 100-\pi } \approx 0.032\]

OpenStudy (danjs):

only about 3.2% chance

OpenStudy (danjs):

0 is no chance, and 1 is garunteed 100% , so it is very much closer to zero than 1

OpenStudy (nuccioreggie):

So thats the answer for part A

OpenStudy (danjs):

yea

OpenStudy (danjs):

part b is less work, since you know the chance of hitting the circle is 0.032, then the chance of hitting the white area is 1 - (chance of circle) = 1 - 0.032 = much closer to 1 for the white region

OpenStudy (danjs):

Because it is assumed he hits the board somewhere every throw , i guess, no missing

OpenStudy (danjs):

so (chance circle) + (Chance white) = 1

OpenStudy (nuccioreggie):

Can you explain Part A again please

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!