For the following reaction, identify the substances being oxidized and reduced (including their oxidation numbers), the oxidizing agent, and reducing agent.

CH4 + 2O2 yields CO2 + 2H2O

Question

For the following reaction, identify the substances being oxidized and reduced (including their oxidation numbers), the oxidizing agent, and reducing agent. 

CH4 + 2O2 yields CO2 + 2H2O

rushwr · Answer

hey wt do u think the answer is?

anonymous · Answer

Idk I need someone to help me through it

rushwr · Answer

okai 1st wt u should do is calculate the oxidation numbers of the reactants

rushwr · Answer

calculate and tell me the oxidation numbers of C H and O

photon336 · Answer

Oxidizing agent is something that causes another Element to be oxidized but it's reduced.

If it causes the other element to be oxidized it must be reduced in the profess, i.e it gains electrons.

Reducing agent is something that causes the other element to be reduced, but is itself oxidized.

So it donates electrons to the other element to reduce it, so it becomes oxidized.