What is the period?

$ \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) $

Is the period $ \huge frac{2\pi}{\frac{2\pi}{365}} $ which would be 365??

Question

What is the period?

$ \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) $

Is the period  $ \huge frac{2\pi}{\frac{2\pi}{365}} $  which would be 365??

anonymous · Answer

What is the period?

$ \huge y = 10 \sin(\frac{2\pi}{365}(x-50)) $

Is the period  $ \huge \frac{2\pi}{\frac{2\pi}{365}} $  which would be 365??

anonymous · Answer

@phi

phi · Answer

if you manipulate the coeff of x into the form
$$ \frac{2\pi}{T} x $$
then T is the period

phi · Answer

you have 2pi/365 
the 365 matches T

so yes, the period is 365

anonymous · Answer

Ok, so 365 is T so does the 50 compress the period?

anonymous · Answer

Or is shifts it to the left

phi · Answer

no the -50 * 2pi/365  is a phase shift
(moves the curve to the right)

anonymous · Answer

Ok thanks so we have T = 365 with a phase shift to the right

phi · Answer

the red curve is the sin without the -50 term
the black curve is yours.

anonymous · Answer

Thank you!