Question

Judy drove 20 miles from her house to a theater at an average rate of 50 miles per hour. Greg drove from his house to the theater in 1/3 of the time it took Judy to drive to the theater, and they arrived at the same time. If Judy left the house at 7:30 pm, when did Greg leave the house?

Answer 1

speed = distance /time

Answer 2

Is it multiple choice?

Answer 3

I knew that but go on

Answer 4

no

Answer 5

I believe it's 7:46pm

Answer 6

i need to know how to do it i dont need the answer

Answer 7

K so

Answer 8

It took judy 24 minutes to get to the theatre and it took greg 1/3 of that.

Answer 9

You would divide 24/3 to get 8.

Answer 10

If Judy left at 7:30 then she got to the theater 24 minutes later at 7:54. That means Greg had to leave his house at 7:46 in order to arrive at the same time.

Answer 11

Because they both left at the same time and greg traveled 1/3 the distance it took Greg 8 minutes to get to the Theatre.

Answer 12

I hope that helps.

Answer 13

Here:

Answer 14

Going at 50mph is would take Judy 24 minutes (2/5 of an hour) to go 20 miles. If Greg got to the theater in 1/3 the time, then that's 8 minutes.

If Judy left at 7:30 then she got to the theater 24 minutes later at 7:54. That means Greg had to leave his house at 7:46 in order to arrive at the same time.

Answer 15

Do you understand or need more help?