Question

HELP!!!!
Find the foci of 16y^2-36x^2-576=0. Then graph the hyperbole.

Answer 1

move -576 to the right side, what do you get?

Answer 2

Positive 576

Answer 3

yes, now, divide both sides by 576, what do you get?

Answer 4

1/36y^2-1/16x^2

Answer 5

=??

Answer 6

=1?

Answer 7

\[\dfrac{y^2}{6^2}-\dfrac{x^2}{4^2}=1\]
right?

Answer 8

yeah

Answer 9

Hence, its b =6, a =4 ok?

Answer 10

yes

Answer 11

foci c, \(c=\sqrt{a^2+b^2}=??\)

Answer 12

thanks can you stay with me for just a second i need to write this down

Answer 13

ok is it square root of 52

Answer 14

You need know where c is. Your equation has y first, hence its graph is vertical, right? Hence foci will be (0, -c) and (0,c) . Yes for c =sqrt 52