Question

(a+b)/(a-b)^-1

Answer 1

I have to simplify this complex fraction

Answer 2

\[\frac{a+b}{\left(a-b\right)^{-1}}=\left(a+b\right)\left(a-b\right)\]

Answer 3

a+b/ a^-1 - b^-1 is the actual question

Answer 4

\[\mathrm{Apply\:exponent\:rule}:\quad \:a^{-1}=\frac{1}{a}\]
\[\left(a-b\right)^{-1}=\frac{1}{a-b}\]
\[=\frac{a+b}{\frac{1}{a-b}}\]
\[\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}\]
\[\frac{a+b}{\frac{1}{a-b}}=\frac{\left(a+b\right)\left(a-b\right)}{1}\]

Answer 5

\[\frac{a+b}{a^{-1}b^{-1}}=ab\left(a+b\right)\]

Answer 6

that is the question

Answer 7

minus sign between variables in the denomitor

Answer 8

\[\frac{a+b}{a^{-1}-b^{-1}}=\frac{ab\left(a+b\right)}{-a+b}\]

Answer 9

are you ok @ailen

Answer 10

how did you get that

Answer 11

\[\mathrm{Simplify}\:\frac{a+b}{a^{-1}-b^{-1}}:\quad \frac{a+b}{\frac{1}{a}-\frac{1}{b}}\]
\[\mathrm{Combine\:the\:fractions\:using\:the\:LCD}:\quad \frac{1}{a}-\frac{1}{b}=\frac{-a+b}{ab}\]

Answer 12

\[=\frac{a+b}{\frac{-a+b}{ab}}\]
\[=\frac{ab\left(a+b\right)}{-a+b}\]
that is the answer

Answer 13

are you understand @ailen

Answer 14

@DecentNabeel is correct

Answer 15

i totally understood thank you so much

Answer 16

Can you help me on another one please

Answer 17

yes he will lol

Answer 18

(3x+1/x) / (2x - 1/x^2)

Answer 19

https://www.symbolab.com/solver/trigonometric-equation-calculator/%5Cfrac%7B%5Cleft(%5Cfrac%7B3x%2B1%7D%7Bx%7D%5Cright)%7D%7B%5Cleft(%5Cfrac%7B2x-1%7D%7Bx%5E%7B2%7D%7D%5Cright)%7D/?origin=button

Answer 20

Does it show me step by step ?