Help with algebra?
Rationalize the denominator and simplify. \[\frac{ 3\sqrt{6}+5\sqrt{2} }{ 4\sqrt{6}-3\sqrt{2} }\] I know I need to multiply by the conjugate.\[\frac{ 4\sqrt{6}+3\sqrt{2} }{ 4\sqrt{6}+3\sqrt{2} }\] I tried doing all of the math but I must have made a mistake at some point because the answer I got does not fit.
yes we need to multiply by the conjugate. then we need to foil afterwards \[\frac{ 3\sqrt{6}+5\sqrt{2} }{ 4\sqrt{6}-3\sqrt{2} } \cdot \frac{ 4\sqrt{6}+3\sqrt{2} }{ 4\sqrt{6}+3\sqrt{2} }\]
hello @MrNood
(a+b)(a-b) = a^2-b^2 so that is simpler than using FOIL for the denominator
the denominator will always been simpler though. because the middle terms from FOIL are gone leaving F L
Ok I know I need to do that and for the numerator I got \[102+18\sqrt{3}+40\sqrt{3}\] and on the denominator I got 78 but that doesn't fit.
|dw:1437553510720:dw| try compute that for the numerator.. while I work out the denominator
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